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  4. The perpendicular distance of the point (6, 5, 8) from y-axis is

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Q. The perpendicular distance of the point (6, 5, 8) from y-axis is

KEAMKEAM 2007Introduction to Three Dimensional Geometry

Solution:

Perpendicular distance of the point (6, 5, 8) from y-axis
$ =\sqrt{{{6}^{2}}+{{8}^{2}}}=\sqrt{36+64}=\sqrt{100} $ =10 unit