Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The period of the function f(x)= sin 4x+ cos 4x is:
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The period of the function $ f(x)={{\sin }^{4}}x+{{\cos }^{4}}x $ is:
Jamia
Jamia 2005
A
$ \pi $
B
$ \frac{\pi }{2} $
C
$ 2\pi $
D
none of these
Solution:
$ f(x)={{\sin }^{4}}x+{{\cos }^{4}}x $ $ ={{({{\sin }^{2}}x+{{\cos }^{2}}x)}^{2}}-2{{\sin }^{2}}x{{\cos }^{2}}x $ $ =1-\frac{1}{2}{{(\sin 2x)}^{2}}=1-\frac{1}{2}\left[ \frac{1-\cos 4x}{2} \right] $ $ =\frac{3}{4}+\frac{1}{4}\cos 4x $ Since, $ \cos x $ is periodic with period $ 2\pi $ $ \therefore $ The period off $ f(x)=\frac{2\pi }{4}=\frac{\pi }{2} $