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  4. The period of oscillation of a simple pendulum of constant length at surface of the earth is T. Its time period inside a mine will be :

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Q. The period of oscillation of a simple pendulum of constant length at surface of the earth is T. Its time period inside a mine will be :

MGIMS WardhaMGIMS Wardha 2005

Solution:

Time period of a simple pendulum at the surface of earth, $ T=2\pi \sqrt{\frac{l}{g}} $ $ T\propto \frac{1}{\sqrt{g}} $ In a mine (below the surface of earth) value of 'g' will decrease, so time period 'T' will increase.