Thank you for reporting, we will resolve it shortly
Q.
The perimeter of triangle with vertices at $(1,0,0)$, $(0,1,0)$ and $(0,0,1)$ is ...P... . Here, $P$ refers to
Introduction to Three Dimensional Geometry
Solution:
Let $A=(1,0,0), B=(0,1,0)$ and $C=(0,0,1)$
Now, $ A B=\sqrt{(1-0)^2+(0-1)^2+0^2}=\sqrt{2}$
$B C=\sqrt{0^2+(1-0)^2+(0-1)^2}=\sqrt{2}$
and $ C A=\sqrt{(0-1)^2+0^2+(1-0)^2}=\sqrt{2}$
$\therefore$ Perimeter of triangle $=A B+B C+C A$
$=\sqrt{2}+\sqrt{2}+\sqrt{2}$
$=3 \sqrt{2}$