Thank you for reporting, we will resolve it shortly
Q.
The perimeter of a certain sector of a circle is equal to the length of the arc of the semicircle. Then the angle at the centre of the sector in radians is
Let the radius of circle be $r$.
$\therefore \,\,\,$ Length of an arc $=\frac{\theta}{360^{\circ}} \times 2\,\pi r$
Since, perimeter of a sector of a circle $ =$ length of the arc of the semicircle.
$\therefore \,\,\,\, \frac{\theta}{360^{\circ}} \times 2 \pi r+2 r=\pi r$
$\Rightarrow \,\,\,\,\, \theta+2=\pi$
$\Rightarrow \,\,\,\,\, \theta=\pi-2$