Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The percentage of pyridine (C5H5N) that forms pyridinium ion (C5H5N+H) in a 0.10 M aqueous pyridine solution (Kb for C5H5N = 1.7 × 10-9) is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The percentage of pyridine $(C_5H_5N)$ that forms pyridinium ion $(C_5H_5N^+H)$ in a $0.10\, M$ aqueous pyridine solution ($K_b$ for $C_5H_5N = 1.7 \times 10^{-9}$) is
NEET
NEET 2016
Equilibrium
A
0.0060%
6%
B
0.013%
62%
C
0.77%
25%
D
1.6%
7%
Solution:
$\alpha=\sqrt{\frac{ K _{ b }}{ C }}$
$=\sqrt{\frac{1.7 \times 10^{-9}}{0.1}}$
$=\sqrt{1.7 \times 10^{-8}}$
$=1.3 \times 10^{-4}$
$=1.3 \times 10^{-2} \%$