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Q. The percentage of carbon atom in acetic acid is:

BHUBHU 2001

Solution:

Acetic acid $\left( CH _{3} COOH \right)$ contains $2 C$ atoms Molecular mass of $CH _{3} COOH$
$=12+1 \times 3+12+16 \times 2+1=60$
$\because 60 \,g$ of $CH _{3} COOH$ contains $24\, g$ of carbon atom
$ \therefore 100\, g $ of $ CH _{3} COOH$ contains $=\frac{24}{60} \times 100 $
$=40 \% $