1. Tardigrade
  2. Question
  3. Chemistry
  4. The percentage hydrolysis of 0.15 M solution of ammonium acetate, Ka for CH3COOH is 1.8 × 10-5 and Kb for NH3 is 1.8 × 10-5

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The percentage hydrolysis of $0.15\, M$ solution of ammonium acetate, $K_a$ for $CH_3COOH $ is $1.8 \times 10^{-5}$ and $K_b$ for $NH_3$ is $1.8 \times 10^{-5}$

BITSATBITSAT 2016

Solution:

$\alpha = \sqrt{\frac{K_{W}}{K_{a} \times K_{b}}} $
$= \sqrt{\frac{1\times10^{-14}}{1.8 \times10^{-5} \times 1.8 \times10^{-5}} } = 0.55 $