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Q. The peak value of 220 volts of a.c mains is:

Alternating Current

Solution:

As we know
$V _{ rms }=\frac{ V _{0}}{\sqrt{2}}$
(Peak) $V _{0}=\sqrt{2} \times V _{ rms }$
$=1.41 \times 220$
$V _{0}=311$ volts