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Q. The partial pressure of nitrogen in air is $0.76\, atm$. and its Henry’s law constant is $7.6 \times 10^4$ atm at 300 K. What is the mole fraction of $N_2$ in the solution obtained when air is bubbled through water at 300 K?

KEAMKEAM 2014Solutions

Solution:

$P_{N_{2}}=0.76 atm$
$K _{ H }=7.6 \times 10^{4}$
$x =?$
$P_{N_{2}}= K \cdot x$
$0.76=7.6 \times 10^{4} \times$
$x =0.76 /\left(7.6 \times 10^{4}\right)=1 \times 10^{-5}$