Q.
The oxidation states of $S$ atoms in $S_{4} O^{2-}_6$ from left to right respectively are
Redox Reactions
Solution:
The structure of $S_{4}O^{2-}_{6}$ ion is
The two S atoms which are linked to each other have O.N. of zero. The O.N. of other two $S$ atoms can be calculated as follows :
$-2 + x+ 2(-2) + 0 + 0 + x + 2 (-2)- 2 = -2$ or $2x- 12 = -2$ or $2x = 10$ or $x = + 5 $ Thus, option (c) is correct.
