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Q. The oxidation states of $ Mn $ in $ MnS{{O}_{4}},Mn{{O}_{2}} $ $ {{K}_{2}}Mn{{O}_{4}} $ and $ KMn{{O}_{4}} $ are respectively

AMUAMU 1995

Solution:

: $ MnS{{O}_{4}}:+x-2=0\Rightarrow x=+2. $ $ Mn{{O}_{2}}:x+2(-2)\Rightarrow x-4=0\Rightarrow x=+4 $ $ {{K}_{2}}Mn{{O}_{4}}:(+1)\times 2+x+(-2)\times 4 $ $ \Rightarrow $ $ +2+x-8\Rightarrow x=+6. $