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Q. The oxidation states of iodine in $HIO_4, H_3IO_5$ and $H_5IO_6$ are respectively

Redox Reactions

Solution:

Calculating the oxidation states of $I$, we get
$H _5 IO _6 ; 5+ x -12=0 $ or $ x =+7$
$H _3 IO _5 ; 3+x-10=0$ or $x =+7$
$HIO _4 ; 1+ x -8=0$ or $x =+7$
Thus, the correct answer is $+7,+7,+7$