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  4. The oxidation state of Pt in Xe+ [PtF6]- is

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Q. The oxidation state of $Pt$ in $Xe^+ [PtF_6]^-$ is

The p-Block Elements - Part2

Solution:

$[PtF_6]^{-1}$
$X + 6(-1) = -1 ; X = +5$