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  4. The oxidation state of Ni in N(CO)4 is

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Q. The oxidation state of $Ni$ in $N(CO)_{4}$ is

AMUAMU 2001

Solution:

Let the oxidation number of $Ni$ is $x$ in $Ni ( CO )_{4}$.
So, $x+4(0) =0$
$x =0$
Oxidation number of a metal in carbonyl complex is always zero.