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Q. The oxidation state of Cr in $[Cr(NH_3)_4Cl_2]^+$ is :

AIEEEAIEEE 2005Coordination Compounds

Solution:

$[Cr(NH_3)_4Cl_2]^+$
Let oxidation state of $Cr = x$
$NH_3 = 0$
$Cl =- 1$
Net charge $= + \,1$
$\therefore \quad\quad$ $[Cr(NH_3)_4Cl_2]^+$
$x + 4 \times 0 +2(-1)= + 1$
$\therefore \quad\quad x = 3$