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Q.
The oxidation state of chromium in $Cr ( CO )_{6}$ is
Redox Reactions
Solution:
Let $x$ be the oxidation state of $Cr$ in $Cr ( CO )_{6}$.
Since, the overall charge on the complex is 0 , the sum of oxidation states of all elements in it should be equal to 0 .
Therefore,
$x +6(0)=0$
or, $x =0$
Hence, the oxidation state of $Cr$ in $Cr ( CO )_{6}$ is 0.