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Chemistry
The oxidation state of chlorine in KClO4 is
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Q. The oxidation state of chlorine in $ KClO_{4} $ is
AMU
AMU 2007
A
- 1
B
+ 1
C
+ 7
D
- 7
Solution:
Let the oxidation state of $Cl$ is $x$.
$ KClO_{4} $
$1 + x + 4 (-2) = 0 $
$1 + x - 8 = 0 $
$x - 7 = 0$
$x = + 7$