Q. The oxidation potentials of following half-cell reactions are given $Zn \rightarrow Zn ^{2+}+2 e^{-} ; E^{\circ}=0.76\, V , Fe \rightarrow Fe ^{2+}+$ $2 e^{-} ; E^{\circ}=0.44\, V$ what will be the emf of cell, whose cell reaction is $Fe ^{2+}( aq .)+ Zn \rightarrow Zn ^{2+}( aq .)+ Fe$
Electrochemistry
Solution: