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Q.
The oxidation number of sulphur, chromium and nitrogen in $H _{2} SO _{5}, Cr _{2} O _{7}^{2-}$ and $NO _{3}^{-}$respectively are
Redox Reactions
Solution:
Thus, the oxidation number of $S , Cr$ and $N$ in $H _{2} SO _{5}$, $Cr _{2} O _{7}^{2-}$ and $NO _{3}^{-}$, respectively are $+6,+6$ and $+5$.
In the structure of $H _{2} SO _{5}$, two oxygen atoms form peroxide linkage, so oxidation number of these O-atoms is $-1$.