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Q. The oxidation number of nitrogen in $ N{{H}_{4}} $ and $ N{{O}_{3}} $ is:

Rajasthan PMTRajasthan PMT 1996

Solution:

The oxidation number of N in $ N{{H}_{4}}^{+} $ $ =x+4=+1 $ $ =x=-3 $ The oxidation number of N in $ N{{O}_{3}}^{-} $ $ x-6=-1 $ $ x=5 $