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  4. The oxidation number of nitrogen in (N2H5)+ is

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Q. The oxidation number of nitrogen in $(N_2H_5)^+$ is

Redox Reactions

Solution:

$\left(N_{2}H_{5}\right)^{+}\Rightarrow 2x + 5 = + 1 \Rightarrow 2x = -4 \Rightarrow $ or, $x = -2$