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  4. The oxidation number of nitrogen atoms in NH4NO3 are

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Q. The oxidation number of nitrogen atoms in $NH_4NO_3$ are

KCETKCET 2020Redox Reactions

Solution:

$NH _{4} NO _{3}$ is a salt. The cationic part is $NH _{4}{ }^{+}$ and the anionic part is $NO _{3}^{-}$.

In $NH _{4}{ }^{+}$, let the oxidation number be $x$. So,

$x+4=1$

$\Rightarrow x =-3$

In $NO^- _{3}$, let the oxidation number be $y$. So,

$y-6=-1$

$\Rightarrow y=+5$