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Q. The oxidation number of Cr in $K_{2} Cr_{2} O_{7}$ is

Redox Reactions

Solution:

$K_{2} \overset {*}{C}r_{2} O_{7}$
$2+ 2x-2 \times 7 =0; 2x -14+2 =0$
$2x =12; x=\frac{12}{2}=+6$