Thank you for reporting, we will resolve it shortly
Q.
The oxidation number of $Cr\, in\, CrO_5$ is
Redox Reactions
Solution:
In $CrO _{5}$, one oxygen is attached to $Cr$ through the double bond. It has oxidation number - 2. Four oxygen atoms are attached to Cr atom through a single bond. Each of these oxygen has an oxidation number $-1$.
Let $x$ be the oxidation number of chromium. The sum of all the oxidation numbers is zero.
Hence, $x-2+4(-1)=0$ and $x=6$
Thus, the oxidation number of chromium in $CrO _{5}$ is $+6$.
