Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The oxidation number of cobalt in $ {{K}_{3}}[Co{{(N{{O}_{2}})}_{6}}] $ is:

EAMCETEAMCET 1998

Solution:

$ {{K}_{3}}[Co{{(N{{O}_{2}})}_{6}}]\xrightarrow{{}} $ or $ 3{{K}^{+}}+{{[Co{{(N{{O}_{2}})}_{6}}]}^{3-}} $ Now, $ {{[Co{{(N{{O}_{2}})}_{6}}]}^{3-}} $ $ \because $ In $ \text{NO}_{2}^{-}, $ oxidation state of $ \text{NO}_{2}^{-}=-1 $ $ x+(-1\times 6)=-3 $ $ x-6=-3 $ $ x=+6-3=+3 $