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Q. The ovule during its development undergoes $ 90{}^\circ $ curvature bringing the micropyle and chalaza in a line but a right angle to the funicle. The ovule development conforms to

AMUAMU 1996

Solution:

: In hemianatropous ovules the body of the ovule is turned through 90°, so that the micropyle and chalaza are on a horizontal line and the funicle lies at right angles to this line. Atropous ovule is upright with micropyle, chalaza and funicle falling in a straight line. In anatropus ovules due to unilateral growth of funicle, the whole body of the ovule is inverted through $ 180{}^\circ $ . As a result the micropyle comes close to the base of the funicle. The nucellus remains straight, i.e., micropyle and chalaza lie in one line and the funicle lies parallel to it. Campylotropous ovules has a curved body but its curvature is less than that of anatropous ovule.