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Q. The overall reaction for the electralytic production of aluminium may be represented as
$Al _2 O _3( s )+3 C ( s ) \longrightarrow 2 Al ( s )+3 CO ( g )$
At $1000^{\circ} C , \Delta G ^{\circ}$ for the process is $594 \,kJ /$ mole. Calculate the minimum voltage required to produce $2$ mole of $Al$ at this temperature.

General Principles and Processes of Isolation of Elements

Solution:

The relation between $\Delta G ^{\circ}$ and $E$ is $\Delta G ^{\circ}=-n FE ^{\circ}$
In the given reaction $n=6$, then
$E ^{\circ}=\frac{-\Delta G ^{\circ}}{n F }=\frac{-594 \times 10^3\, J / mol }{6 \times 96500\, J / V \cdot mol }=-1.03 \,V$