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Q.
The output of the given circuit in figure
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Case $(1):-$ In forward biased.
The positive half cycle of input $AC$ voltage, the resistance of $p-n$ junction is law. The current in the circuit is maximum. In this situation, a maximum potential difference will appear across resistance connected in series of the circuit. This result into the zero output voltage across p-n junction.
Case $(2):-$ In reverse biased.
The negative half cycle of input $A C$ voltage, the resistance of $p-n$ junction becomes high which will be more than the resistance in series. That's why, there will be voltage drop across $p - n$ junction with negative cycle in output. The output of the given circuit would like that a half- wave rectifier with negative cycle in output.
