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Q.
The output of the given circuit in figure
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
During positive half cycle of input $A C$ voltage, the $p-n$ junction is forward biased. The resistance of $p-n$ junction is low. The current in the circuit is maximum. In this situation, a maximum potential difference will appear across resistance connected in series of circuit. Due to it, there is no output voltage across $p-n$ junction.
During the negative half-cycle of input $AC$ voltage the $p-n$ junction is reverse biased. The resistance of $p-n$ junction becomes high which will he more than resistance in series. Due to it, there will be voltage across $p-n$ junction with negative cycle in output.
