Q. The output of a $NOR$ gate is HIGH when
TS EAMCET 2020
Solution:
The Boolean expression of $NOR$ gate is
$Y=\overline{A+B}$
where, $A$ and $B$ are inputs and $Y$ is the output.
Truth table of $NOR$ gate is
$A$
$B$
$Y =\overline{ A + B }$
$0$
$0$
$1$
$0$
$1$
$0$
$1$
$0$
$0$
$1$
$1$
$0$
Hence, when all inputs $(A$ and $B)$ are low $(0)$, then output of $NOR$ gate is high $(1)$.
$A$ | $B$ | $Y =\overline{ A + B }$ |
$0$ | $0$ | $1$ |
$0$ | $1$ | $0$ |
$1$ | $0$ | $0$ |
$1$ | $1$ | $0$ |