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Q. The output of a $NOR$ gate is HIGH when

TS EAMCET 2020

Solution:

The Boolean expression of $NOR$ gate is
$Y=\overline{A+B}$
where, $A$ and $B$ are inputs and $Y$ is the output.
Truth table of $NOR$ gate is
$A$ $B$ $Y =\overline{ A + B }$
$0$ $0$ $1$
$0$ $1$ $0$
$1$ $0$ $0$
$1$ $1$ $0$

Hence, when all inputs $(A$ and $B)$ are low $(0)$, then output of $NOR$ gate is high $(1)$.