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Q.
The osmotic pressure of blood is 7.65 atm. at 310 K. An aqueous solution of glucose which is isotonic with blood has the percentage (wt./volume)
Solutions
Solution:
Since glucose and blood are isotonic, the osmotic pressures are the same. Therefore, $\pi_{\text{glucose}}=\pi_{\text{blood}}$
Or $7.65 \times V =\frac{w}{180}\times 0.0821 \times 310$ [w = amount of glucose present in V litres of solution]
Or $7.65\times 180 =\frac{w}{V}\times 0.0821\times 310$
Or $\frac{w}{V}=\frac{7.65 \times 180}{0.0821 \times 310}$
$=54.1\,g\, L^{-1}$ or $5.41 \%$