Question

The oscillations represented by curve 1 in the graph are expressed by equation $x=A \sin \omega t$. The equation for the oscillations represented by curve 2 is expressed as:

• A. $x=2 A \sin (\omega t-\pi / 2)$
• B. $x=2 A \sin (\omega t+\pi / 2)$
• C. $x=-2 A \sin (\omega t-\pi / 2)$
• D. $x=A \sin (\omega t-\pi / 2)$

Answer 1

Answer: (A)

Oscillations represented by curve $2$ lags in phase by $\pi / 2$ and the periods are same. Amplitude of curve $2$ is double that of $1$ .