Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The oscillating frequency of a cyclotron is 10 MHz . If the radius of its Dees is 0.5 m , the kinetic energy of a proton, which is accelerated by the cyclotron is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The oscillating frequency of a cyclotron is $ 10 \,MHz $ . If the radius of its Dees is $ 0.5 \,m $ , the kinetic energy of a proton, which is accelerated by the cyclotron is
KEAM
KEAM 2008
Moving Charges and Magnetism
A
10.2 MeV
16%
B
2.55 MeV
0%
C
20.4 MeV
11%
D
5.1 MeV
58%
E
1.5 MeV
58%
Solution:
KE of charged possible in a cyclotron,
$ {{E}_{k}}=\frac{{{q}^{2}}{{B}^{2}}{{r}^{2}}}{2m} $
But frequency $ f=\frac{qB}{2\pi m} $
$ \therefore $ $ {{E}_{k}}=\frac{{{(2\pi mf)}^{2}}{{r}^{2}}}{2m}=2{{\pi }^{2}}m{{f}^{2}}{{r}^{2}} $
Or $ {{E}_{k}}=2\times {{(3.14)}^{2}}\times 1.67\times {{10}^{-27}}\times {{(10\times {{10}^{6}})}^{2}} $
$ \times {{(0.5)}^{2}} $
$ =8.23\times {{10}^{-13}}J $
$ \therefore \,\,{{E}_{k}}\,=\frac{8.23\,\times {{10}^{-13}}}{1.6\,\times {{10}^{-19}}\,}\, $
$ =5.1\,\times {{10}^{6}}\,eV=5.1\,MeV $