Q. The orthocentre of the triangle formed by (0,0), (8, 0) and (4, 6) is
JamiaJamia 2014
Solution:
Line perpendicular to OA passing through B is $ x=4 $ .
Slope of $ AB=-\frac{3}{2} $ Line perpendicular to AB and passes through origin is $ y=\frac{2}{3}x $ $ \therefore $ The point of intersection of a line x = 4 and $ y=\frac{2}{3}x $ is $ \left( 4,\frac{8}{3} \right) $ , which is the required orthocentre.
