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Q. The organic product formed in the reaction$C_6CH_5COOH \xrightarrow[{(II)H_3O^+}]{(I)LiAlH_4}$

Aldehydes Ketones and Carboxylic Acids

Solution:

$LiAlH_4$ is a reducing agent, it reduces $-COOH$ group to $-CH_2OH$ group.
$C_6CH_5COOH \xrightarrow{LiAlH_4} C_6H_5CH_2OH$