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Chemistry
The organic product formed in the reactionC6CH5COOH xrightarrow[(II)H3O+](I)LiAlH4
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Q. The organic product formed in the reaction$C_6CH_5COOH \xrightarrow[{(II)H_3O^+}]{(I)LiAlH_4}$
Aldehydes Ketones and Carboxylic Acids
A
$C_6H_5CH_2OH$
0%
B
$C_6H_5I + CH_3OH$
100%
C
$C_6H_5CH_3 + HOI$
0%
D
$C_6H_5 + CH_3OH$
0%
Solution:
$LiAlH_4$ is a reducing agent, it reduces $-COOH$ group to $-CH_2OH$ group.
$C_6CH_5COOH \xrightarrow{LiAlH_4} C_6H_5CH_2OH$