Question

The order of stability of the following alkenes with the first being the most stable and last being the least stable is
$ I. CH_3CH_2CH =CH_2 $
$ II. (CH_3)_2C= C(CH_3)_2 $
$ III. CH_3CH = C (CH_3)_2 $
$ IV.(CH_3)_2C = CH_2 $

• A. $ I > II > III > IV $
• B. $ II > III > IV > I $
• C. $ IV > III > II > I $
• D. $ III > IV > I > II $

Answer 1

Answer: (B)

Greater the substituents across double bond of alkenes greater is the stability
Thus, order of stability of given alkenes is :
$\underset{II} {{\left(CH_{3}\right)_{2} C}}= C(CH_{3})_{2} >\, \underset{III}{{CH_{3}CH=C(CH_{3})_{2}}} > \, \underset{IV}{{(CH_{3})_{2}C=CH_{2}}} >\, \underset{I}{{CH_{3}CH_{2}CH = CH_{2}}}$