Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The order and degree of the following differential equation [1+((dy/dx))2]5/2 = (d3y/dx3) are respectively
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The order and degree of the following differential equation $\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5/2} = \frac{d^{3}y}{dx^{3}}$ are respectively
WBJEE
WBJEE 2008
Differential Equations
A
$3, 2$
44%
B
$3, 10$
12%
C
$2, 3$
3%
D
$3, 5$
41%
Solution:
Given differential equation is
$\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5/2} = \frac{d^{3}y}{dx^{3}} $
$\Rightarrow \left(\frac{d^{3}y}{dx^{3}}\right)^{2} = \left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{5}$
From above it is clear that the order and degree of the given differential equation are $3$ and $2$ respectively.