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Q.
The order and degree of the differential equation $\left(\frac{d^{3}y}{dx^{3}}\right) = 2\frac{d^{2}y}{dx^{2}}+\sqrt[3]{cos^{2}\,x}$ are, respectively
Given differential equation is
$\left(\frac{d^{3} y}{d x^{3}}\right)^{1 / 3}=2 \frac{d^{2} y}{d x^{2}}+\sqrt[3]{\cos ^{2} x}$
On cubing both sides, we get
$\left(\frac{d^{3} y}{d x^{3}}\right)=\left(2 \frac{d^{2} y}{d x^{2}}+\sqrt[3]{\cos ^{2} x}\right)^{3}$
Here, we see that the highest order derivative is 3 and whose degree is 1 .