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Physics
The orbital frequency of an electron in the hydrogen atom is proportional to
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Q. The orbital frequency of an electron in the hydrogen atom is proportional to
MHT CET
MHT CET 2010
Atoms
A
$ n^3 $
29%
B
$ n^{-3} $
43%
C
$ n^1 $
19%
D
$ n^0 $
10%
Solution:
Time period of electron, $ T=\frac {4 \varepsilon_0^2n^3h^3}{mZ^2e^4} $
$ \therefore T \propto n^3 $
$ \therefore \frac {1}{\text{frequency} \, (f)} \propto n^3 $
or $ f \propto n^{-3} $