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Q. The orbital angular momentum of an electron in $3s-$ orbital is:

NTA AbhyasNTA Abhyas 2022

Solution:

$\sqrt{\ell \left(\ell + 1\right)}\frac{h}{2 \pi }$ for $s\left(\ell = 0\right)\Rightarrow O.A.M.=\frac{h}{2 \pi }\left(0\right)=0$