Given, figure shows the relation between speed and time. So, area of the figure will be displacement.
Therefore, area of first triangular
$\left(d_{1}\right)=\frac{1}{2} \times 10 \times 10=50\, m$,
area of second triangular
$\left(d_{2}\right)=\frac{1}{2} \times(-10) \times 10=-50\, m$
Therefore, total area $(d) =$ total displacement of particle
$\Rightarrow d_{1}+d_{2}=50-50=0$