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Q. The observed rotation of $2 \,g$ of a compound in $10\, mL$ of solution in polarimeter tube of $25\, cm$ long is $+134^{\circ}$. What is the specific rotation in degree?

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$[\alpha]_{T}^{\lambda}=\frac{q}{d \times l}=\frac{134}{\frac{2}{10} \times \frac{25}{10}}=26.8^{\circ}$