Thank you for reporting, we will resolve it shortly
Q.
The number of words of four letters containing equal number of vowels and consonants, where repetition is allowed, is
Permutations and Combinations
Solution:
Let us first select two places for vowel, which can be selected from $4$ places in $^4C_2$ ways. Now this places can be filled by vowels in $5 \times 5 = 25$ ways as repetition is allowed. The remaining two places can be filled by consonants in $21 \times 21$ ways. Then the total number of words is $^4C_2 \times 25 \times 21^2
= 150 \times 21^2$.