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Q. The number of ways of arranging $8$ men and $4$ women around a circular table such that no two women can sit together, is

NTA AbhyasNTA Abhyas 2020Permutations and Combinations

Solution:

The number of ways of arranging $8$ men $=7!$
The number of ways of arranging $4$ women such that no two women can sit together $= \,{}^{8} P_{4}$
$\therefore $ Required number of ways $=7 ! \,{}^{8}P_{4}$