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  4. The number of ways in which 5 girls and 3 boys can be seated in a row so the no two boys are together is

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Q. The number of ways in which 5 girls and 3 boys can be seated in a row so the no two boys are together is

KCETKCET 2018Permutations and Combinations

Solution:

5 girls can be arranged in $5 !=120$ ways
3 boys between 5 girls with positions can be arranged in ${ }^{6} P _{3}=6 \cdot 5 \cdot 4=120$ ways
$\therefore $ Total number of arrangements $=120 \times 120=14400$