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Q. The number of waves in the third orbit of $H$ atom is

Structure of Atom

Solution:

Number of waves $=$ Number of shell
Number of waves $=-\frac{\text { Circumference }}{\text { de Broglie } \lambda}$ $\lambda=\frac{ h }{ mv }$
Number of waves $=\frac{2 \pi r \times m v}{h}$
$m v r=\frac{n h}{2 \pi}$
Number of waves $= n$
Number of waves in third orbit $=3$