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  4. The number of water molecules present in a drop of water weighing 0.018 gm is

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Q. The number of water molecules present in a drop of water weighing $0.018\, gm$ is

KCETKCET 2013Some Basic Concepts of Chemistry

Solution:

$18\, g$ of $H _{2} O =1 \,mol$ of $H _{2} O =6.022 \times 10^{23}$ molecules

$0.018\, g$ of $H _{2} O =\frac{0.018}{18} \,mol$ of $H _{2} O$

$=\frac{0.018}{18} \times 6.022 \times 10^{23}$ molecules

$=6.022 \times 10^{20}$ molecules