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  4. The number of water molecules present in a drop of water (volume 0.0018 mL) density = 18 mL-1 at room temperature is

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Q. The number of water molecules present in a drop of water (volume 0.0018 mL) density = 18 $mL^{-1}$ at room temperature is

Structure of Atom

Solution:

$0.0018 \,mL = 0.0018\, g = 0.0001$ mole of water
$= 1 \times 10^{-4} mole$.
$\therefore $ number of water molecules
$= 6.023 \times 10^{23} \times 10^{-4}$
$= 6.023 \times 10^{19}$