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Q. The number of values of $c$ such that the straight line $y = 4x + c$ touches the curve $\frac{x^2}{ 4} + y^2 = 1$ is

IIT JEEIIT JEE 1998Conic Sections

Solution:

For ellipse, condition of tangency is $c^2 = a^2m^2 + b^2 $
Given line is $y = 4x + c$ and curve $ \frac{ x^2 }{ 4} + y^2 = 1 $
$\Rightarrow c^2 = 4 \times 4^2 +1 = 65 $
$\Rightarrow c= \pm \sqrt{65}$